Are you an EPFL student looking for a semester project?
Work with us on data science and visualisation projects, and deploy your project as an app on top of Graph Search.
Concept
Distance from a point to a plane
Summary
In Euclidean space, the distance from a point to a plane is the distance between a given point and its orthogonal projection on the plane, the perpendicular distance to the nearest point on the plane.
It can be found starting with a change of variables that moves the origin to coincide with the given point then finding the point on the shifted plane that is closest to the origin. The resulting point has Cartesian coordinates :
The distance between the origin and the point is .
Suppose we wish to find the nearest point on a plane to the point (), where the plane is given by . We define , , , and , to obtain as the plane expressed in terms of the transformed variables. Now the problem has become one of finding the nearest point on this plane to the origin, and its distance from the origin. The point on the plane in terms of the original coordinates can be found from this point using the above relationships between and , between and , and between and ; the distance in terms of the original coordinates is the same as the distance in terms of the revised coordinates.
The formula for the closest point to the origin may be expressed more succinctly using notation from linear algebra. The expression in the definition of a plane is a dot product , and the expression appearing in the solution is the squared norm . Thus, if is a given vector, the plane may be described as the set of vectors for which and the closest point on this plane to the origin is the vector
The Euclidean distance from the origin to the plane is the norm of this point,
In either the coordinate or vector formulations, one may verify that the given point lies on the given plane by plugging the point into the equation of the plane.
To see that it is the closest point to the origin on the plane, observe that is a scalar multiple of the vector defining the plane, and is therefore orthogonal to the plane.
Thus, if is any point on the plane other than itself, then the line segments from the origin to and from to form a right triangle, and by the Pythagorean theorem the distance from the origin to is
Since must be a positive number, this distance is greater than , the distance from the origin to .
About this result
This page is automatically generated and may contain information that is not correct, complete, up-to-date, or relevant to your search query. The same applies to every other page on this website. Please make sure to verify the information with EPFL's official sources.