Summary
In atmospheric, earth, and planetary sciences, a scale height, usually denoted by the capital letter H, is a distance (vertical or radial) over which a physical quantity decreases by a factor of e (the base of natural logarithms, approximately 2.718). For planetary atmospheres, scale height is the increase in altitude for which the atmospheric pressure decreases by a factor of e. The scale height remains constant for a particular temperature. It can be calculated by or equivalently where: kB = Boltzmann constant = R = gas constant T = mean atmospheric temperature in kelvins = 250 K for Earth m = mean mass of a molecule (units kg) M = mean mass of one mol of atmospheric particles = 0.029 kg/mol for Earth g = acceleration due to gravity at the current location (m/s2) The pressure (force per unit area) at a given altitude is a result of the weight of the overlying atmosphere. If at a height of z the atmosphere has density ρ and pressure P, then moving upwards an infinitesimally small height dz will decrease the pressure by amount dP, equal to the weight of a layer of atmosphere of thickness dz. Thus: where g is the acceleration due to gravity. For small dz it is possible to assume g to be constant; the minus sign indicates that as the height increases the pressure decreases. Therefore, using the equation of state for an ideal gas of mean molecular mass M at temperature T, the density can be expressed as Combining these equations gives which can then be incorporated with the equation for H given above to give: which will not change unless the temperature does. Integrating the above and assuming P0 is the pressure at height z = 0 (pressure at sea level) the pressure at height z can be written as: This translates as the pressure decreasing exponentially with height. In Earth's atmosphere, the pressure at sea level P0 averages about 1.01e5Pa, the mean molecular mass of dry air is 28.964 u and hence m = 28.964 × 1.660e-27 = 4.808e-26kg. As a function of temperature, the scale height of Earth's atmosphere is therefore H/T = k/mg = (1.
About this result
This page is automatically generated and may contain information that is not correct, complete, up-to-date, or relevant to your search query. The same applies to every other page on this website. Please make sure to verify the information with EPFL's official sources.