Lecture
This lecture presents the solution to exercise 12, focusing on finding the values of C for which -1 is an eigenvalue of a parameterized 3 by 3 matrix. The instructor explains the logic behind determining the eigenvalue and demonstrates the algebraic steps to solve for the determinant of the matrix. By carefully working through the calculations, it is shown that the value of C needs to be -2 for -1 to be an eigenvalue of the matrix.